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• Neuchrist Maximilian|Steiner Maik x Rodrigo Alujas/Julien De Cuyper Statistik

Neuchrist Maximilian|Steiner Maik vs Rodrigo Alujas/Julien De Cuyper statistik 18.02.2025

• 18/02/25 12:35
• 

  Maximilian Neuchrist/ Maik Steiner
  • 2 : 0
  • Selesai
  

  Rodrigo Alujas/ Julien De Cuyper

T

1

2

Neuchrist Maximilian|Steiner Maik

2

6

6

Rodrigo Alujas/Julien De Cuyper

0

4

0

Neuchrist Maximilian|Steiner Maik

Stats

Rodrigo Alujas/Julien De Cuyper

• Pertandingan
• Tetapkan 1
• Tetapkan 2

Melayani

2

Aces

1

1

Kesalahan ganda

6

63%

Persentase servis pertama

63%

21/2584%

Poin servis pertama %

19/2966%

11/1573%

Poin servis kedua %

5/1729%

3/3100%

Poin break %

2/633%

Kembali

10/2934%

Poin pengembalian pertama %

4/2516%

12/1771%

Poin pengembalian kedua %

4/1527%

4/667%

Poin break %

0/30%

Poin

0/00%

Poin di net %

0/00%

32/4080%

Poin servis %

24/4652%

22/4648%

Poin pengembalian %

8/4020%

54/8663%

Poin total %

32/8637%

Permainan

8/8100%

Permainan servis %

4/850%

4/850%

Permainan pengembalian %

0/80%

12/1675%

Permainan total %

4/1625%

Neuchrist Maximilian|Steiner Maik

Н2Н

Rodrigo Alujas/Julien De Cuyper

Semua turnamen All matches

Tidak ada yang cocok

Ini adalah pertandingan pertama dari para pemain ini

Hasil terakhir: Neuchrist Maximilian|Steiner Maik

Challenger Men - Doubles Brazzaville 2

WP 19/02/25 10:15

Barreiros Reyes Mateo|Saraiva Dos Santos Paulo Andre

• 10
• 6
• 1

2 Neuchrist Maximilian|Steiner Maik

• 3
• 3
• 6

1

WP 18/02/25 12:35

Neuchrist Maximilian|Steiner Maik

• 6
• 6

2 Rodrigo Alujas/Julien De Cuyper

• 0
• 4

0

ITF Men - Doubles M25 Heraklion 3 2

WP 07/11/24 07:25

Sakellaridis Michalis|Sakellaridis Dimitris

• 6
• 6

2 Neuchrist Maximilian|Steiner Maik

• 2
• 3

0

WP 05/11/24 04:30

Neuchrist Maximilian|Steiner Maik 0 Cezar Cretu/Bogdan Pavel 0

Hasil terakhir: Rodrigo Alujas/Julien De Cuyper

Challenger Men - Doubles Brazzaville 1

WP 18/02/25 12:35

Neuchrist Maximilian|Steiner Maik

• 6
• 6

2 Rodrigo Alujas/Julien De Cuyper

• 0
• 4

0