Turnamen teratas

Finals - Turin

ATP - Singles

Finals - Riyadh

WTA - Singles

US Open

ATP - Singles

US Open

WTA - Singles

Australian Open

ATP - Singles

Australian Open

WTA - Singles

Roland Garros

ATP - Singles

Roland Garros

WTA - Singles

Wimbledon

ATP - Singles

Wimbledon

WTA - Singles

Six Kings Slam

Exhibition - Men

Semua negara
ATP - Doubles
ATP - Singles
Boys - Doubles
Boys - Singles
Challenger Men - Doubles
Challenger Men - Singles
Challenger Women - Doubles
Challenger Women - Singles
Exhibition - Doubles Men
Exhibition - Doubles Women
Exhibition - Men
Exhibition - Mixed Doubles
Exhibition - Teams
Exhibition - Women
Girls - Doubles

Girls - Singles
ITF Men - Doubles
ITF Men - Singles
ITF Women - Doubles
ITF Women - Singles
Mixed Doubles
Teams - Men
Teams - Mix
Teams - Women
WTA - Doubles
WTA - Singles

Menampilkan lebih banyak

Kalender

Peringkat

Perlombaan Ganda ATP

Perlombaan Ganda WTA

Tenis
ITF Women - Doubles
W25 Austin, TX
Kozyreva M./Lahey A. x Beck C./Harrison C. Bagan turnamen

Kozyreva M./Lahey A. - Beck C./Harrison C. 17.11.2023

17/11/23 16:45
Maria Kozyreva/ Ashley Lahey
- 2 : 0
- Selesai
Chloe Beck/ Catherine Harrison

T

1

2

Kozyreva M./Lahey A.

2

6

7

Beck C./Harrison C.

0

3

5

1/8-finals

Kozyreva M./Lahey A. (1)

Allen K./Failla J.

Mia Kupres/Mary Stoiana

Chavatipon C./Rapolu M.

Beck C./Harrison C. (3)

Ovrootsky V./Sasnouskaya T.

Friedman L./Shcherbinina A.

Sahdiieva A./Yamalapalli S.

Martha Matoula/Martina Okalova

Ly-Nguyen S./Verma R.

Jiangxue Han/Yujia Huang

Mushika Mao/Zyryanova A. (4)

Kendall E./Ukaegbu A.

Pachkaleva T./Rivkin N.

Evans T./Miyamoto A.

Kononova M./Markham A. (2)

Quarter-finals

Kozyreva M./Lahey A. (1)

Mia Kupres/Mary Stoiana

Beck C./Harrison C. (3)

Sahdiieva A./Yamalapalli S.

Martha Matoula/Martina Okalova

Jiangxue Han/Yujia Huang

Pachkaleva T./Rivkin N.

Kononova M./Markham A. (2)

Semi-finals

Kozyreva M./Lahey A. (1)

Beck C./Harrison C. (3)

Jiangxue Han/Yujia Huang

Pachkaleva T./Rivkin N.

Final

Kozyreva M./Lahey A. (1)

Jiangxue Han/Yujia Huang

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